# Solving Problems Using Elimination

This is why substitution is most useful when the problem already contains an isolated variable or if there is at least a variable that has a coefficient of one.If you can solve basic algebra equations very quickly, substitution is a good choice.We perform elemental operations in the rows to obtain the reduced row echelon form: We multiply the first row by 1/5 and the second by 1/3 We add the second row with the first We multiply the second row by 5/7 We add the first row with the second one multiplied by -2/5 This last equivalent matrix is in the reduced row echelon form and it allows us to quickly see the rank of the coefficient matrix and the augmented one.

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Now, how do we know that a linear equation obtained by the addition of the first equation with a scalar multiplication of the second is equivalent to the first?

In this section we are going to solve systems using the Gaussian Elimination method, which consists in simply doing elemental operations in row or column of the augmented matrix to obtain its echelon form or its reduced echelon form (Gauss-Jordan).

Note: The elemental operations in rows or columns allow us to obtain equivalent systems to the initial one, but with a form that simplifies obtaining the solutions (if there are).

Also, there are quicker tools to work out the solutions in the CIS, like Cramer's rule.

Kathryn White has over 11 years of experience tutoring a range of subjects at the kindergarten through college level.

Her writing reflects her instructional ability as well as her belief in making all concepts understandable and approachable.This method involves plugging an expression from one equation in for the variable in another.To use this method, at least one variable in one of the equations must be isolated.Methods for solving systems include substitution, elimination, and graphing.Each one will give the right answer but is more or less useful depending on the problem and situation.In contrast, if neither equation has Y isolated, you are better off using substitution or elimination.Using a graphing calculator to enter both equations and find the point of intersection comes in handy when they involve decimals or fractions.The bottom equation is then subtracted from the top one to cancel out a variable.This makes elimination efficient when the constants of both equations are already isolated.To create this article, volunteer authors worked to edit and improve it over time. This article can explain how to perform to achieve the solution for both variables. Have you ever had a simultaneous problem equation you needed to solve?

## Comments Solving Problems Using Elimination

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